1. 化简: $\sqrt{6-3 \sqrt{3}}+\sqrt{6+3 \sqrt{3}}$ 的结果是 ( )
A. 6
B. $\sqrt{6}$
C. $3 \sqrt{3}$
D. $3 \sqrt{2}$

Question

1. 化简: $\sqrt{6-3 \sqrt{3}}+\sqrt{6+3 \sqrt{3}}$ 的结果是 ( )
A. 6
B. $\sqrt{6}$
C. $3 \sqrt{3}$
D. $3 \sqrt{2}$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ To simplify the expression $$\sqrt{6-3\sqrt{3}}+\sqrt{6+3\sqrt{3}}$$, we recognize that both terms under the square roots are of the form $$a^2 - b^2$$ and $$a^2 + b^2$$ respectively, where $$a = \sqrt{3}$$ and $$b = \sqrt{3}$$ ‖ ‖ step 2 ⋮ We can rewrite the terms as $$\sqrt{3(2-\sqrt{3})} + \sqrt{3(2+\sqrt{3})}$$ ‖ ‖ step 3 ⋮ Factoring out the common term $$\sqrt{3}$$, we get $$\sqrt{3}(\sqrt{2-\sqrt{3}} + \sqrt{2+\sqrt{3}})$$ ‖ ‖ step 4 ⋮ The expression simplifies to $$3\sqrt{2}$$, as the terms inside the parentheses combine to form a conjugate pair, which results in the simplification of the square roots ‖ ***D*** ∻Key Concept∻ ⚹Conjugate Pairs⚹ ∻Explanation∻ ⚹When simplifying square roots of the form $$\sqrt{a+b}$$ and $$\sqrt{a-b}$$, where $$a$$ and $$b$$ are positive real numbers, the sum of these roots can often be simplified by recognizing them as conjugate pairs. This allows for the simplification of the square roots and often results in a rational number.⚹◊What are the steps involved in simplifying the expression $ \sqrt{6-3 \sqrt{3}} + \sqrt{6+3 \sqrt{3}} $?⍭ Generate me a similar question◊

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