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15240672380's Question
Posted 3 months ago

11) In an experiment, (120+Y)mL0.6MNa2SO4(120+\mathrm{Y}) \mathrm{mL} 0.6 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4} solution is mixed with 300 mL0.45MBaCl2300 \mathrm{~mL} 0.45 \mathrm{M} \mathrm{BaCl}_{2} solution and BaSO4\mathrm{BaSO}_{4} precipitate (solid) is formed according to the below reaction. Calculate the amount of precipitate in grams. . (Atomic mass: Na=23,O=16, S=32,Ba=137,Cl=35\mathrm{Na}=23, \mathrm{O}=16, \mathrm{~S}=32, \mathrm{Ba}=137, \mathrm{Cl}=35 )
Na2SO4(aq)+BaCl2(aq)2NaCl(aq)+BaSO4( s)
\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{BaCl}_{2}(\mathrm{aq}) \rightarrow 2 \mathrm{NaCl}(\mathrm{aq})+\mathrm{BaSO}_{4}(\mathrm{~s})
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Answer from Sia
Posted 3 months ago
Write the balanced chemical equation: The balanced chemical equation for the reaction between sodium sulfate and barium chloride is Na2SO4(aq)+BaCl2(aq)2NaCl(aq)+BaSO4(s) \mathrm{Na_2SO_4(aq) + BaCl_2(aq) \rightarrow 2NaCl(aq) + BaSO_4(s)}
Calculate moles of reactants: Use the molarity and volume to calculate the moles of Na2SO4\mathrm{Na_2SO_4} and BaCl2\mathrm{BaCl_2}. For Na2SO4\mathrm{Na_2SO_4}, moles = molarity ×\times volume in liters = 0.6M×(120+Y)mL×1L1000mL0.6 \, \mathrm{M} \times (120+Y) \, \mathrm{mL} \times \frac{1 \, \mathrm{L}}{1000 \, \mathrm{mL}}. For BaCl2\mathrm{BaCl_2}, moles = 0.45M×0.3L0.45 \, \mathrm{M} \times 0.3 \, \mathrm{L}
Determine the limiting reactant: The stoichiometry of the reaction is 1:1, so the reactant with fewer moles is the limiting reactant
Calculate moles of precipitate: The moles of BaSO4\mathrm{BaSO_4} precipitate will be equal to the moles of the limiting reactant due to the 1:1 stoichiometry
Calculate mass of precipitate: Use the molar mass of BaSO4\mathrm{BaSO_4} to convert moles to grams. Molar mass of BaSO4\mathrm{BaSO_4} = 137+32+4×16137 + 32 + 4 \times 16. Mass = moles of BaSO4\mathrm{BaSO_4} ×\times molar mass of BaSO4\mathrm{BaSO_4}
[Insert final answer here after calculating with the value of Y]
Key Concept
Limiting reactant determines the amount of product formed in a chemical reaction.
The amount of BaSO4\mathrm{BaSO_4} precipitate is calculated by finding the limiting reactant and using its moles to find the mass of the precipitate.

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