2. A new element with atomic number 116 was discovered in 2000 . In 2012 it was named livermorium, Lv. Although $\mathrm{Lv}$ is radioactive and short-lived, its chemical properties and reactivity should follow periodic trends.
a. Write the electron configuration for the valence electrons of $\mathrm{Lv}$ in the ground state.
b. According to periodic properties, what would be the most likely formula for the product obtained when Lv reacts with $\mathrm{H}_{2}(\mathrm{~g})$ ?
c. The first ionization energy of polonium, Po, is $812 \mathrm{~kJ} / \mathrm{mol}$. Is the first ionization energy of $\mathrm{Lv}$ expected to be greater than, less than, or equal to that of Po? Justify your answer in terms of Coulomb's law.
d. Shown below is a hypothetical mass spectrum for a sample of $\mathrm{Lv}$ containing 10 atoms.
Using the information in the graph, determine the average atomic mass of $\mathrm{Lv}$ in the sample to four significant figures.

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Sure, let's address each part of the student's question one by one. ### Part a: Electron Configuration for Valence Electrons of Lv ***A*** ∻Key Concept∻ ⚹Electron Configuration⚹ ∻Explanation∻ ⚹The valence electron configuration for Livermorium (Lv) in the ground state is $7s^2 7p^4$.⚹ ### Part b: Most Likely Formula for the Product with $H_2(g)$ ***B*** ∻Key Concept∻ ⚹Periodic Trends and Reactivity⚹ ∻Explanation∻ ⚹Based on periodic trends, Livermorium (Lv) is in the same group as oxygen and sulfur, which form $H_2O$ and $H_2S$ respectively. Therefore, the most likely formula for the product when Lv reacts with $H_2(g)$ is $H_2Lv$.⚹ ### Part c: First Ionization Energy of Lv Compared to Po ***C*** ∻Key Concept∻ ⚹Coulomb's Law and Ionization Energy⚹ ∻Explanation∻ ⚹According to Coulomb's law, the ionization energy depends on the effective nuclear charge and the distance of the valence electrons from the nucleus. Since Livermorium (Lv) is below Polonium (Po) in the periodic table, it has more electron shells, which increases the distance of the valence electrons from the nucleus and decreases the effective nuclear charge. Therefore, the first ionization energy of Lv is expected to be less than that of Po.⚹ ### Part d: Average Atomic Mass of Lv ***D*** ∻Key Concept∻ ⚹Average Atomic Mass Calculation⚹ ∻Explanation∻ ⚹To calculate the average atomic mass, use the formula: $ ext{Average Atomic Mass} = \frac{\sum ( ext{Atomic Mass} imes ext{Number of Atoms})}{ ext{Total Number of Atoms}}$. For the given data: $(291.0 imes 2) + (292.0 imes 3) + (293.0 imes 5) = 582 + 876 + 1465 = 2923$. The total number of atoms is $2 + 3 + 5 = 10$. Therefore, the average atomic mass is $\frac{2923}{10} = 292.3$ amu.⚹◊What is the electron configuration for the valence electrons of livermorium (Lv) in the ground state?⍭ Generate me a similar question◊

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