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Question
Math
Posted 5 months ago

2. Let y=f(x)y=f(x) be the solution to the differential equation dydx=1+2y\frac{d y}{d x}=1+2 y with the initial condition f(0)=1f(0)=1. What is the approximation for f(1)f(1) if Euler's method is used, starting at x=0x=0 with a step size of 0.5 ?
(A) 2.5
(B) 3.5
(C) 4.0
(D) 5.5
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Answer from Sia
Posted 5 months ago
Solution by Steps
step 1
We start with the differential equation dydx=1+2y\frac{d y}{d x} = 1 + 2y and the initial condition f(0)=1f(0) = 1
step 2
Using Euler's method, we approximate the solution at x=1x = 1 with a step size of h=0.5h = 0.5
step 3
The formula for Euler's method is yn+1=yn+hf(xn,yn)y_{n+1} = y_n + h \cdot f(x_n, y_n)
step 4
At x=0x = 0, y0=1y_0 = 1. We calculate y1y_1 using y1=y0+h(1+2y0)y_1 = y_0 + h \cdot (1 + 2y_0)
step 5
Substituting the values, y1=1+0.5(1+21)=1+0.53=1+1.5=2.5y_1 = 1 + 0.5 \cdot (1 + 2 \cdot 1) = 1 + 0.5 \cdot 3 = 1 + 1.5 = 2.5
step 6
Now, we calculate y2y_2 at x=1x = 1 using y2=y1+h(1+2y1)y_2 = y_1 + h \cdot (1 + 2y_1)
step 7
Substituting the values, y2=2.5+0.5(1+22.5)=2.5+0.56=2.5+3=5.5y_2 = 2.5 + 0.5 \cdot (1 + 2 \cdot 2.5) = 2.5 + 0.5 \cdot 6 = 2.5 + 3 = 5.5
Answer
5.5
Key Concept
Euler's Method
Explanation
Euler's method is a numerical technique for solving ordinary differential equations by approximating solutions at discrete points.

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