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Question
Math
Posted 6 months ago
2. Let y=f(x)y=f(x) be the solution to the differential equation dydx=1+2y\frac{d y}{d x}=1+2 y with the initial condition f(0)=1f(0)=1. What is the approximation for f(1)f(1) if Euler's method is used, starting at x=0x=0 with a step size of 0.5 ?
(A) 2.5
(B) 3.5
(C) 4.0
(D) 5.5
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Answer from Sia
Posted 6 months ago
Solution by Steps
step 1
Apply Euler's method to the differential equation dydx=1+2y\frac{dy}{dx} = 1 + 2y with initial condition y(0)=1y(0) = 1 and a step size of 0.5
step 2
Calculate the value of yy at x=0.5x = 0.5. Use the formula ynext=ycurrent+step_sizedydxxcurrent,ycurrenty_{next} = y_{current} + step\_size \cdot \frac{dy}{dx}|_{x_{current}, y_{current}}
step 3
For the first step, ycurrent=1y_{current} = 1 and dydxxcurrent,ycurrent=1+21=3\frac{dy}{dx}|_{x_{current}, y_{current}} = 1 + 2 \cdot 1 = 3. Thus, ynext=1+0.53=2.5y_{next} = 1 + 0.5 \cdot 3 = 2.5
step 4
Now calculate the value of yy at x=1x = 1. Again use the formula from step 2 with the new ycurrent=2.5y_{current} = 2.5 and dydxxcurrent,ycurrent=1+22.5=6\frac{dy}{dx}|_{x_{current}, y_{current}} = 1 + 2 \cdot 2.5 = 6
step 5
For the second step, ynext=2.5+0.56=5.5y_{next} = 2.5 + 0.5 \cdot 6 = 5.5
Answer
(D) 5.5
Key Concept
Euler's Method for Approximating Solutions to Differential Equations
Explanation
Euler's method uses the slope of the tangent line at known points to estimate the value of the function at the next point, using a given step size.

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