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$P=4 \mathrm{kN}$ $M=3 \mathrm{kN} \mathrm{m}$ $q=1 \mathrm{kN} / \mathrm{m}$ Reaction: $Y_{A}$
б)
A
C
角.

Question

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Given the equation $4 \cos(60°) + Y_A = 2q + P$, we need to solve for $Y_A$. ‖ ‖ step 2 ⋮ Substitute the given values $P = 4 \, ext{kN}$ and $q = 1 \, ext{kN/m}$ into the equation. ‖ ‖ step 3 ⋮ The equation becomes $4 \cos(60°) + Y_A = 2(1) + 4$. ‖ ‖ step 4 ⋮ Simplify the equation by calculating $\cos(60°)$, which is $0.5$, and then multiply by $4$ to get $2$. ‖ ‖ step 5 ⋮ The simplified equation is $2 + Y_A = 2 + 4$. ‖ ‖ step 6 ⋮ Combine like terms to get $Y_A = 4$. ‖ ∻Answer∻ ⚹ $Y_A = 4 \, ext{kN}$ ⚹ ∻Key Concept∻ ⚹Solving linear equations with one variable⚹ ∻Explanation∻ ⚹To find the value of $Y_A$, we substituted known values into the equation and solved for the unknown variable using basic algebraic operations.◊What is the equation for calculating the reaction force at point A in diagram a)?⍭ Generate me a similar question◊⚹

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