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shane89191's Question
Chemistry
Posted 5 months ago
27个分子,其中A的分配比为2:1,B的分配比为1:2,求4次流动相的推动平衡后分子在两相中的分布
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Answer from Sia
Posted 5 months ago
Solution
1
Determine the total number of molecules: Given that there are 27 molecules in total, we need to find out how many molecules of A and B there are initially
2
Calculate initial distribution of A and B: The ratio of A to B is given as 2:1 for A and 1:2 for B. This means for every 3 parts of A, there is 1 part of B and vice versa. To find the initial number of A and B molecules, we solve the system of equations: 2x+y=272x + y = 27 for A and x+2y=27x + 2y = 27 for B, where xx is the number of A molecules and yy is the number of B molecules
3
Solve the system of equations: Solving the equations 2x+y=272x + y = 27 and x+2y=27x + 2y = 27 simultaneously gives us the initial number of A and B molecules
4
Apply the distribution ratios: After each movement of the mobile phase, the distribution of A and B between the two phases will change according to their respective ratios. For A, the ratio is 2:1, meaning that after each movement, twice as many A molecules will be in one phase compared to the other. For B, the ratio is 1:2, meaning that after each movement, twice as many B molecules will be in the opposite phase compared to A
5
Calculate the distribution after 4 movements: We need to apply the distribution ratios 4 times to find the final distribution of A and B molecules in the two phases
Answer
The detailed calculations are required to provide the final distribution of A and B molecules after 4 movements of the mobile phase.
Key Concept
The distribution of molecules between two phases in chromatography can be predicted using the given distribution ratios and applying them over multiple movements of the mobile phase.
Explanation
The question involves applying the concept of ratios and equilibrium distribution in a chromatographic process, where the distribution ratios dictate how molecules of different substances are separated between two phases.

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