(2)
For the Velocity / Time graph given below.
20
Velocity
IS
time
(mr)
10
(s)
12
11
S
10
9
12345678
0
-5
-10
State the time(s) when the object
(a)
is accelerating 0-2
(i)
is decelerating 6-8
(ii)
is moving with constant veocity 2-6
(iii)
is not moving 82018
(iv)
is moving backwards 8-129
(v)
Calculate the acceleration
(b)
for the first 2 s. 10amls
(i)
0-20 = -20 2 -10mls
at 8 S.
(ii)
8-86
Calculate the displacement for the first 6s. 20+80=100
(c)
Calculate the total distance travelled. 120+5=125
(d)
Calculate the final displacement. 120-5-115
(e)
(3) Sketch the Displacement/Time, Velocity/Time and Acceleration/Time graphs for a ball thrown vertically
upwards at 20 m/s.

Question

(2)
For the Velocity / Time graph given below.
20
Velocity
IS
time
(mr)
10
(s)
12
11
S
10
9
12345678
0
-5
-10
State the time(s) when the object
(a)
is accelerating 0-2
(i)
is decelerating 6-8
(ii)
is moving with constant veocity 2-6
(iii)
is not moving 82018
(iv)
is moving backwards 8-129
(v)
Calculate the acceleration
(b)
for the first 2 s. 10amls
(i)
0-20 = -20 2 -10mls
at 8 S.
(ii)
8-86
Calculate the displacement for the first 6s. 20+80=100
(c)
Calculate the total distance travelled. 120+5=125
(d)
Calculate the final displacement. 120-5-115
(e)
(3) Sketch the Displacement/Time, Velocity/Time and Acceleration/Time graphs for a ball thrown vertically
upwards at 20 m/s.

Accepted Answer

I'm here to help you with your question about the Velocity/Time graph. Let's break it down step by step. (a) - The object is accelerating from 0-2 seconds. - The object is decelerating from 6-8 seconds. - The object is moving with constant velocity from 2-6 seconds. - The object is not moving from 8-20 seconds. - The object is moving backwards from 8-12 seconds. (b) - To calculate the acceleration for the first 2 seconds, we use the formula: acceleration = change in velocity / time. - So, for the first 2 seconds, the acceleration is -10 m/s^2. (c) - To calculate the displacement for the first 6 seconds, we need to find the area under the velocity/time graph. - The total displacement for the first 6 seconds is 100 meters. (d) - The total distance traveled is 125 meters. (e) - I can help you sketch the Displacement/Time, Velocity/Time, and Acceleration/Time graphs for a ball thrown vertically upwards at 20 m/s. Let's work on that together. Feel free to ask if you have any more questions or need further clarification!

Sia