4
-
If
1
0
ml of KOHlag was used to titrate
1
5
ml of
0
.
1
M KHP solution the molar concentration ofKOH solution is:
a
)

1
.
5
M
c
)

0
.
1
5
M
b
)

1
5
*
1
0
^
-
3
M
d
)

0
.
6
7
M

Question

4
-
 ﻿If 
1
0
ml of KOHlag was used to titrate 
1
5
ml of 
0
.
1
M KHP solution the molar concentration ofKOH solution is:
a
)
 
1
.
5
M
c
)
 
0
.
1
5
M
b
)
 
1
5
*
1
0
^
-
3
 ﻿M
d
)
 
0
.
6
7
M

Accepted Answer

***B*** ∻Key Concept∻ ⚹Stoichiometry of a titration reaction⚹ ∻Explanation∻ ⚹The molarity of the KOH solution can be found using the stoichiometry of the titration reaction with KHP (potassium hydrogen phthalate). Since KHP has one acidic hydrogen, the reaction with KOH is 1:1. Using the volume and molarity of KHP, we can find the moles of KHP, which equals the moles of KOH. Then, using the volume of KOH, we can calculate its molarity.⚹◊What is the balanced chemical equation for the reaction between KOH and KHP?⍭ Generate me a similar question◊

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