8.) Find the mass percent of $\mathrm{FeCl}_{3}$ in a solution whose density is $1.42 \mathrm{~g} / \mathrm{mL}$ and whose molarity is $1.19 \mathrm{M}$.

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∻Solution∻ ‖ 1 ⋮ **Calculate the mass of 1 liter of solution**: Given the density of the solution is $1.42 \, ext{g/mL}$, we can calculate the mass of 1 liter (1000 mL) of the solution. ‖ ‖ $ ext{Mass} = ext{Density} imes ext{Volume} = 1.42 \, ext{g/mL} imes 1000 \, ext{mL} = 1420 \, ext{g} $ ‖ ‖ 2 ⋮ **Calculate the mass of $\mathrm{FeCl}_{3}$ in 1 liter of solution**: The molarity (M) is the number of moles of solute per liter of solution. We can use the molarity to find the mass of $\mathrm{FeCl}_{3}$ in 1 liter. The molar mass of $\mathrm{FeCl}_{3}$ is $55.845 \, ext{g/mol} + 3 imes 35.453 \, ext{g/mol} = 162.204 \, ext{g/mol}$. ‖ ‖ $ ext{Moles of } \mathrm{FeCl}_{3} = 1.19 \, ext{M} = 1.19 \, ext{moles/L} $ ‖ ‖ $ ext{Mass of } \mathrm{FeCl}_{3} = ext{Moles} imes ext{Molar Mass} = 1.19 \, ext{moles} imes 162.204 \, ext{g/mol} = 193.02276 \, ext{g} $ ‖ ‖ 3 ⋮ **Calculate the mass percent of $\mathrm{FeCl}_{3}$**: The mass percent is the mass of the solute divided by the total mass of the solution, multiplied by 100. ‖ ‖ $ ext{Mass percent} = \left( \frac{ ext{Mass of } \mathrm{FeCl}_{3}}{ ext{Mass of solution}} ight) imes 100 = \left( \frac{193.02276 \, ext{g}}{1420 \, ext{g}} ight) imes 100 $ ‖ ∻Answer∻ ⚹ 13.59% ⚹ ∻Key Concept∻ ⚹ Mass percent of a solute in a solution ⚹ ∻Explanation∻ ⚹ The mass percent is calculated by dividing the mass of the solute by the total mass of the solution and multiplying by 100. ⚹◊What is the formula to calculate the mass percent of $FeCl_{3}$ in a solution?⍭ Generate me a similar question◊

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