Question

Chemistry

Posted 4 months ago

`9) with (30+Y) $\mathrm{g} \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ (molar mass $\left.=310 \mathrm{~g} / \mathrm{mol}\right)$, what is the maximum volume of the solution with a concentration of $0.375 \mathrm{M}$ ?`

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Answer from Sia

Posted 4 months ago

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Answer

The maximum volume of the solution with a concentration of $0.375 \mathrm{M}$ that can be prepared from $(30+Y) \mathrm{g}$ of $\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2$ is $\frac{(30+Y) / 310}{0.375}$ liters.

Key Concept

Molarity and solution preparation

Explanation

Molarity (M) is a measure of the concentration of a solute in a solution, defined as the number of moles of solute per liter of solution. To find the maximum volume of a solution with a given molarity, one must first calculate the moles of solute available and then divide by the molarity.

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