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Biology
Posted 9 months ago

A 100 mL100 \mathrm{~mL} volume of tryptone broth is inoculated with 0.5 mL0.5 \mathrm{~mL} of overnight culture of E\mathrm{E}. coli. Following the reading of a sample's absorbance, a serial dilution is then performed by transferring 0.6 mL0.6 \mathrm{~mL} from the sample into 9.4 mL9.4 \mathrm{~mL} of tryptone broth. That diluted sample is vortexed, and 0.5 mL0.5 \mathrm{~mL} is withdrawn and diluted into a second tube, containing 5.5 mL5.5 \mathrm{~mL} of trypt
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Answer from Sia
Posted 9 months ago
Answer
The dilution process described involves two steps, resulting in a final dilution factor of 1:220.
Solution
a
Initial Dilution: The first dilution involves adding 0.6 mL0.6 \mathrm{~mL} of the overnight culture to 9.4 mL9.4 \mathrm{~mL} of tryptone broth, creating a dilution factor of 100.6=16.6\frac{10}{0.6} = 16.\overline{6} or approximately 1:17
b
Second Dilution: The second dilution involves taking 0.5 mL0.5 \mathrm{~mL} of the first dilution and adding it to 5.5 mL5.5 \mathrm{~mL} of broth, resulting in a dilution factor of 60.5=12\frac{6}{0.5} = 12
c
Total Dilution Factor: To find the total dilution factor, multiply the dilution factors of both steps: 16.6×12=20016.\overline{6} \times 12 = 200. Therefore, the overall dilution factor is 1:200
Key Concept
Serial dilution is a stepwise dilution of a substance in solution.
Explanation
The overall dilution factor is calculated by multiplying the dilution factors of each step in the serial dilution process.

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