A $5 \mathrm{~mL}$ sample diluted 1:1 with trypan blue is counted using a hemocytometer. A total of 325 viable cells and 52 dead cells were counted in the four corner square and the big central square of the meter. What is the total number of dead cells per $\mathrm{mL}$ of the sample?

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∻Answer∻ ⚹ The total number of dead cells per mL of the sample is 2,600 cells/mL ⚹ ∻Solution∻ ‖ a ⋮ First, calculate the total number of cells counted: $325$ viable cells + $52$ dead cells = $377$ total cells. ‖ ‖ b ⋮ Determine the dilution factor: The sample was diluted 1:1 with trypan blue, so the dilution factor is $2$. ‖ ‖ c ⋮ Calculate the concentration of dead cells in the diluted sample: $\frac{52 ext{ dead cells}}{5 ext{ mL}} = 10.4 ext{ dead cells/mL}$. ‖ ‖ d ⋮ Adjust for the dilution factor: $10.4 ext{ dead cells/mL} imes 2 = 20.8 ext{ dead cells/mL}$. ‖ ‖ e ⋮ Since the hemocytometer counts cells in a specific volume, typically $0.1 ext{ mm}^3$ or $0.1 ext{ \mu L}$, convert this to mL: $20.8 ext{ dead cells/mL} imes 0.1 ext{ mL} = 2.08 ext{ dead cells}$. ‖ ‖ f ⋮ Finally, scale up to the original sample volume: $2.08 ext{ dead cells} imes 125 = 2,600 ext{ dead cells/mL}$. ‖ ∻Key Concept∻ ⚹ Hemocytometer cell counting ⚹ ∻Explanation∻ ⚹ The hemocytometer is a device used to count cells in a specific volume of a sample. By knowing the dilution factor and the volume of the sample, we can calculate the concentration of cells in the original sample. ⚹◊What is the formula to calculate the total number of dead cells per $mL$ of the sample⍭ Generate me a similar question◊

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