A certain shade of blue has a frequency of $7.28 imes 10^{\wedge} 14 \mathrm{~Hz}$. What is the energy of exactly one photon of this light? Plancks constant is $\mathrm{h}=6.626 imes 10^{\wedge}-34 \mathrm{Js}$

Question

A certain shade of blue has a frequency of $7.28 	imes 10^{\wedge} 14 \mathrm{~Hz}$. What is the energy of exactly one photon of this light? Plancks constant is $\mathrm{h}=6.626 	imes 10^{\wedge}-34 \mathrm{Js}$

Accepted Answer

∻Solution∻ ‖ 1 ⋮ **Calculate the energy of one photon**: To find the energy of a photon, use the equation $E = h \cdot f$, where $E$ is the energy of the photon, $h$ is Planck's constant, and $f$ is the frequency of the light. ‖ ‖ 2 ⋮ **Insert the given values**: Substitute the given values into the equation: $E = (6.626 imes 10^{-34} ext{ Js}) \cdot (7.28 imes 10^{14} ext{ Hz})$. ‖ ‖ 3 ⋮ **Perform the calculation**: Multiply the values to find the energy of one photon: $E = (6.626 imes 10^{-34} ext{ Js}) \cdot (7.28 imes 10^{14} ext{ Hz}) = 4.824 imes 10^{-19} ext{ J}$. ‖ ∻Answer∻ ⚹ The energy of exactly one photon of the blue light is $4.824 imes 10^{-19}$ joules. ⚹ ∻Key Concept∻ ⚹ Energy of a photon ⚹ ∻Explanation∻ ⚹ The energy of a photon is calculated by multiplying Planck's constant by the frequency of the light.◊What is the formula to calculate the energy of a photon based on its frequency and Planck's constant⍭ Generate me a similar question◊⚹

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