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青州's Question
Chemistry
Posted 2 months ago

A certain shade of blue has a frequency of 7.28×1014 Hz7.28 \times 10^{\wedge} 14 \mathrm{~Hz}. What is the energy of exactly one photon of this light? Plancks constant is h=6.626×1034Js\mathrm{h}=6.626 \times 10^{\wedge}-34 \mathrm{Js}
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Answer from Sia
Posted 2 months ago
Solution
1
Calculate the energy of one photon: To find the energy of a photon, use the equation E=hfE = h \cdot f, where EE is the energy of the photon, hh is Planck's constant, and ff is the frequency of the light
2
Insert the given values: Substitute the given values into the equation: E=(6.626×1034 Js)(7.28×1014 Hz)E = (6.626 \times 10^{-34} \text{ Js}) \cdot (7.28 \times 10^{14} \text{ Hz})
3
Perform the calculation: Multiply the values to find the energy of one photon: E=(6.626×1034 Js)(7.28×1014 Hz)=4.824×1019 JE = (6.626 \times 10^{-34} \text{ Js}) \cdot (7.28 \times 10^{14} \text{ Hz}) = 4.824 \times 10^{-19} \text{ J}
Answer
The energy of exactly one photon of the blue light is 4.824×10194.824 \times 10^{-19} joules.
Key Concept
Energy of a photon
Explanation
The energy of a photon is calculated by multiplying Planck's constant by the frequency of the light.

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