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Question
Math
Posted 8 months ago

A circle is centered at C(1,3)C(-1,-3) and has a radius of 6 .
Where does the point P(6,6)P(-6,-6) lie?
Choose 1 answer:
(A) Inside the circle
(B) On the circle
(C) Outside the circle
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Answer from Sia
Posted 8 months ago
Solution by Steps
step 2
The distance formula is d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points
step 3
Substituting the coordinates of C(1,3)C(-1,-3) and P(6,6)P(-6,-6) into the distance formula gives d=(6(1))2+(6(3))2=(5)2+(3)2=25+9=34d = \sqrt{(-6 - (-1))^2 + (-6 - (-3))^2} = \sqrt{(-5)^2 + (-3)^2} = \sqrt{25 + 9} = \sqrt{34}
step 4
The calculated distance is 34\sqrt{34}, which is approximately 5.83095
step 5
Since the distance from CC to PP is less than the radius of the circle (6), point PP lies inside the circle
1 Answer
A
Key Concept
Distance Formula and Circle Geometry
Explanation
To determine the position of a point relative to a circle, compare the distance from the point to the center of the circle with the radius of the circle. If the distance is less than the radius, the point is inside the circle.

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