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Question
Math
Posted 7 months ago

A composite function can be written as w(u(x))w(u(x)), where uu and ww are basic functions.

Is f(x)=x4x1f(x)=\frac{\sqrt{x}}{4 x-1} a composite function? If so, what are the "inner" and "outer" functions?

Choose 1 answer:
(A) ff is composite. The "inner" function is 4x14 x-1 and the "outer" function is x\sqrt{x}.
(B) ff is composite. The "inner" function is x\sqrt{x} and the "outer" function is 4x14 x-1.
(c) ff is not a composite function.
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Answer from Sia
Posted 7 months ago
Solution by Steps
step 1
To determine if f(x)=x4x1f(x) = \frac{\sqrt{x}}{4x-1} is a composite function, we need to identify if it can be written in the form w(u(x))w(u(x)), where u(x)u(x) and w(x)w(x) are basic functions
step 2
Let's consider u(x)=xu(x) = \sqrt{x} and w(u)=u4x1w(u) = \frac{u}{4x-1}
step 3
Substituting u(x)u(x) into w(u)w(u), we get w(u(x))=x4x1w(u(x)) = \frac{\sqrt{x}}{4x-1}, which matches f(x)f(x)
step 4
Therefore, f(x)f(x) can be written as a composite function w(u(x))w(u(x)) with u(x)=xu(x) = \sqrt{x} and w(u)=u4x1w(u) = \frac{u}{4x-1}
step 5
The "inner" function is u(x)=xu(x) = \sqrt{x} and the "outer" function is w(u)=u4x1w(u) = \frac{u}{4x-1}
Answer
(B) ff is composite. The "inner" function is x\sqrt{x} and the "outer" function is 4x14x-1.
Key Concept
Composite Function
Explanation
A composite function is formed when one function is applied to the result of another function. In this case, f(x)=x4x1f(x) = \frac{\sqrt{x}}{4x-1} can be expressed as w(u(x))w(u(x)) where u(x)=xu(x) = \sqrt{x} and w(u)=u4x1w(u) = \frac{u}{4x-1}.

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