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Question
Chemistry
Posted 3 months ago

A lab group is given 25.0 grams of an unknown metal. The students are instructed to identify the metal by determining its specific heat capacity. Their unknown must be one of the metals from the following table:
\begin{tabular}{lc} 
Substance & Specific heat (J/gC)\left(\mathrm{J} / \mathrm{g}^{\circ} \mathrm{C}\right) \\
\hline Aluminum & 0.897 \\
Magnesium & 1.024 \\
Silver & 0.235 \\
Zinc & 0.388
\end{tabular}

Using a standard calorimetry set-up and three separate trials, the students report that their sample released -1760 joules of thermal energy when it cooled from 100.0C100.0^{\circ} \mathrm{C} to 21.4C21.4^{\circ} \mathrm{C}.

Specific heat equation \checkmark
What is the likely identity of the metal?

Choose 1 answer:
(A) aluminum
(B) magnesium
(c) silver
(D) zinc
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Answer from Sia
Posted 3 months ago
D
Key Concept
Specific Heat Capacity
Explanation
The specific heat capacity can be calculated using the formula q=mcΔTq = mc\Delta T. Given the thermal energy released (q=1760q = -1760 J), mass (m=25.0m = 25.0 g), and temperature change (ΔT=100.0C21.4C=78.6C\Delta T = 100.0^\circ C - 21.4^\circ C = 78.6^\circ C), we can solve for the specific heat capacity (cc). The calculated specific heat capacity is closest to that of zinc (0.388 J/g°C).

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