A man and a woman, who are both heterozygous for phenylketonuria (PKU), have four children.

What is the probability that all 4 children will have Sickle - cell anemia?
(Hint: Forgot the mode of inheritance for PKU? Then look it up!)

Question

A man and a woman, who are both heterozygous for phenylketonuria (PKU), have four children.

What is the probability that all 4 children will have Sickle - cell anemia?
(Hint: Forgot the mode of inheritance for PKU? Then look it up!)

Accepted Answer

∻Answer∻ ⚹ The probability that all 4 children will have Sickle-cell anemia when both parents are heterozygous for phenylketonuria (PKU) is 0%. ⚹ ∻Solution∻ ‖ a ⋮ PKU inheritance mode: Phenylketonuria (PKU) is inherited in an autosomal recessive pattern. This means that both parents must carry one copy of the mutated gene to pass the disorder to their offspring. ‖ ‖ b ⋮ Sickle-cell anemia inheritance: Sickle-cell anemia is caused by a mutation in the HBB gene, which is unrelated to the gene responsible for PKU. It is also inherited in an autosomal recessive pattern, but the inheritance of PKU does not affect the inheritance of Sickle-cell anemia. ‖ ‖ c ⋮ Probability calculation: Since the question asks about the probability of the children having Sickle-cell anemia, and there is no information provided about the parents' genotype for the HBB gene, we cannot calculate the probability for Sickle-cell anemia based on the information about PKU. ‖ ∻Key Concept∻ ⚹ Different genetic disorders are inherited independently unless they are linked on the same chromosome, which is not the case for PKU and Sickle-cell anemia. ⚹ ∻Explanation∻ ⚹ The probability of all four children having Sickle-cell anemia cannot be determined from the parents' PKU heterozygosity status, as these are two distinct genetic conditions with separate inheritance patterns. ⚹◊What is the mode of inheritance for phenylketonuria (PKU)?⍭ Generate me a similar question◊

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