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Sia

青州's Question
Chemistry
Posted 8 months ago

A sample containing sulfate ions ( SO42\mathrm{SO} 42 - ) is dissolved in water. Precipitation with barium chloride (BaCl2)(\mathrm{BaCl} 2) forms of barium sulfate (BaSO4)(\mathrm{BaSO} 4). Calculate the percentage of sulfate in the original sample
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Answer from Sia
Posted 8 months ago
Solution
1
Write the balanced chemical equation: The precipitation reaction between sulfate ions and barium chloride can be represented by the balanced chemical equation: BaCl2(aq)+SO42(aq)BaSO4(s)+2Cl(aq)\mathrm{BaCl}_2(aq) + \mathrm{SO}_4^{2-}(aq) \rightarrow \mathrm{BaSO}_4(s) + 2\mathrm{Cl}^-(aq)
2
Relate moles of barium sulfate to sulfate ions: From the balanced equation, it is clear that 1 mole of BaSO4\mathrm{BaSO}_4 is produced from 1 mole of SO42\mathrm{SO}_4^{2-}
3
Calculate the mass of sulfate ions: To find the percentage of sulfate in the original sample, we need the mass of SO42\mathrm{SO}_4^{2-} which can be calculated if the mass of BaSO4\mathrm{BaSO}_4 precipitate is known. Assume we have mm grams of BaSO4\mathrm{BaSO}_4. The molar mass of BaSO4\mathrm{BaSO}_4 is 233.39g/mol233.39 \, \mathrm{g/mol} and that of SO42\mathrm{SO}_4^{2-} is 96.06g/mol96.06 \, \mathrm{g/mol}. The mass of SO42\mathrm{SO}_4^{2-} in the precipitate is given by: (96.06233.39)×m\left(\frac{96.06}{233.39}\right) \times m grams
4
Calculate the percentage of sulfate: If the original sample had a mass of MM grams, the percentage of sulfate is: ((96.06233.39)×mM)×100%\left(\frac{\left(\frac{96.06}{233.39}\right) \times m}{M}\right) \times 100\%
Answer
To calculate the percentage of sulfate in the original sample, the mass of the BaSO4\mathrm{BaSO}_4 precipitate and the mass of the original sample are required. Once these values are known, the percentage can be calculated using the formula: ((96.06233.39)×mM)×100%\left(\frac{\left(\frac{96.06}{233.39}\right) \times m}{M}\right) \times 100\%.
Key Concept
Stoichiometry of the precipitation reaction
Explanation
The stoichiometry of the reaction between sulfate ions and barium chloride is used to relate the mass of barium sulfate precipitate to the mass of sulfate ions, which is then used to calculate the percentage of sulfate in the original sample.

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