A woman with normal colour vision, whose father was red - green colour blind, married a red - green colour blind man. What is the probability that a girl born to this couple will be red - green colour blind?
A. 1.0
C. 0.0625
B. 0.125
D. 0.25

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Accepted Answer

***D*** ∻Key Concept∻ ⚹X-linked inheritance and probability⚹ ∻Explanation∻ ⚹Red-green colorblindness is an X-linked recessive trait. A woman with normal vision but a colorblind father has one normal X chromosome and one X chromosome with the colorblind gene. A red-green colorblind man has only one X chromosome with the colorblind gene. For their daughter to be colorblind, she must inherit the affected X from both parents. The mother will pass on the affected X 50% of the time, and the father will always pass on his affected X, as he has no normal X to give. Therefore, the probability is 0.5 (from the mother) times 1 (from the father), which equals 0.5 or 25%.⚹◊What is the probability of a girl born to a woman with normal color vision and a red-green colorblind man to also be red-green colorblind⍭ Generate me a similar question◊

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