Question

Math

Posted 2 months ago

```
Antawn Jamison is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws $73 \%$ of the time.
What is the probability of Antawn Jamison making all of his next 9 free throw attempts?
Choose 1 answer:
(A) $(1-0.73)^{9}$
(b) $9 \cdot 0.73$
(c) $9 \cdot(1-0.73)$
() $0.73^{9}$
```

Sign in to unlock the answer

Answer from Sia

Posted 2 months ago

Solution by Steps

step 2

Calculating the probability: $0.73^9$

step 3

Using the asksia-ll calculator result, the exact probability is $0.058871586708267913$

1 Answer

D

Key Concept

Independent Events in Probability

Explanation

When events are independent, the probability of all events occurring is the product of their individual probabilities. In this case, raising the single event probability to the power of the number of events (9 free throws).

Not the question you are looking for? Ask here!

Enter question by text

Enter question by image

Upgrade to Asksia Pro

Join a AskSia's Pro Plan, and get 24/7 AI tutoring for your reviews, assignments, quizzes and exam preps.

Unlimited chat query usages

Strong algorithms that better know you

Early access to new release features

Study Other Question