Calculate ΔH∘r×n for the reaction below given the enthalpies of formation.
2C12H26(g)+37O2(g)→24CO2(g)+26H2O(g)ΔH∘∘(kJ/mol)C12H26(g)CO2(g)H2O(g)−70−394−242−17350kJ−12590kJ−21850kJ−15610kJ−567kJ
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Answer from Sia
Posted 5 months ago
B
Key Concept
Hess's Law and Enthalpy of Formation
Explanation
The enthalpy change of a reaction (ΔHrxn∘) can be calculated using the standard enthalpies of formation (ΔHf∘) of the reactants and products. The formula is: ΔHrxn∘=∑ΔHf∘(products)−∑ΔHf∘(reactants).
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