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Question
Chemistry
Posted 5 months ago

Calculate the wavelengths of the following objects. A muon (a subatomic particle with a mass of 1.884 \times 1025 g)10-25 \mathrm{~g}) traveling at 389 m/s389 \mathrm{~m} / \mathrm{s} :
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Answer from Sia
Posted 5 months ago
Solution
1
Convert mass to kilograms: The mass of the muon is given in grams and needs to be converted to kilograms for use in the de Broglie wavelength equation. The conversion is 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}. Therefore, the mass of the muon in kilograms is 1.884×1025 g×1 kg1000 g=1.884×1028 kg1.884 \times 10^{-25} \text{ g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 1.884 \times 10^{-28} \text{ kg}
2
Use the de Broglie wavelength equation: The de Broglie wavelength λ\lambda can be calculated using the equation λ=hmv\lambda = \frac{h}{mv}, where hh is Planck's constant (6.626×1034 m2kg/s6.626 \times 10^{-34} \text{ m}^2\text{kg/s}), mm is the mass of the particle in kilograms, and vv is the velocity of the particle in meters per second
3
Calculate the wavelength: Substitute the known values into the de Broglie equation to find the wavelength of the muon. λ=6.626×1034 m2kg/s1.884×1028 kg×389 m/s\lambda = \frac{6.626 \times 10^{-34} \text{ m}^2\text{kg/s}}{1.884 \times 10^{-28} \text{ kg} \times 389 \text{ m/s}}
4
Perform the calculation: After substituting the values, the calculation is λ=6.626×10341.884×1028×3898.85×1013 m\lambda = \frac{6.626 \times 10^{-34}}{1.884 \times 10^{-28} \times 389} \approx 8.85 \times 10^{-13} \text{ m}
Answer
The wavelength of the muon is approximately 8.85×10138.85 \times 10^{-13} meters.
Key Concept
de Broglie wavelength
Explanation
The de Broglie wavelength is the wavelength associated with a particle and can be calculated using the particle's mass and velocity along with Planck's constant.

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