Calculate the weight, in grams, of Agent $P$ required in a static bath treatment of rainbow trout using a dosage of $2 \mathrm{ppm} / \mathrm{hr}$ for a one hour treatment period. The raceway is $15 \mathrm{~m}$ long by $3 \mathrm{~m}$ wide by $2.5 \mathrm{~m}$ deep

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Sure, let's address the question about calculating the weight of Agent P required for the static bath treatment of rainbow trout. ∻Answer∻ ⚹ The weight of Agent P required is 225 grams. ⚹ ∻Solution∻ ‖ a ⋮ Calculate the volume of the raceway: The raceway is 15 meters long, 3 meters wide, and 2.5 meters deep. The volume $V$ is given by $V = ext{length} imes ext{width} imes ext{depth}$. Therefore, $V = 15 \, ext{m} imes 3 \, ext{m} imes 2.5 \, ext{m} = 112.5 \, ext{m}^3$. ‖ ‖ b ⋮ Convert the volume from cubic meters to liters: Since 1 cubic meter is equivalent to 1000 liters, the volume in liters is $112.5 \, ext{m}^3 imes 1000 \, ext{L/m}^3 = 112,500 \, ext{L}$. ‖ ‖ c ⋮ Calculate the dosage in grams: The dosage is given as 2 ppm/hr for a one-hour treatment period. 2 ppm means 2 grams of Agent P per 1,000,000 grams of water. Since the density of water is approximately 1 g/mL, 1 liter of water weighs 1,000 grams. Therefore, $2 \, ext{ppm} = 2 \, ext{g} / 1,000,000 \, ext{g} = 2 \, ext{g} / 1,000 \, ext{L}$. For 112,500 liters, the required weight of Agent P is $2 \, ext{g} imes 112.5 = 225 \, ext{g}$. ‖ ∻Key Concept∻ ⚹ Dosage calculation for a given volume of water in ppm. ⚹ ∻Explanation∻ ⚹ The key concept involves understanding the relationship between ppm (parts per million) and the volume of water to determine the required weight of a substance. In this case, converting the volume of the raceway to liters and then applying the given dosage in ppm allows us to calculate the necessary amount of Agent P. ⚹◊What is the formula to calculate the weight of Agent P required for the static bath treatment of rainbow trout?⍭ Generate me a similar question◊

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