Cora is playing a game that involves flipping three coins at once.
Let the random variable $H$ be the number of coins that land showing "heads". Here is the probability distribution for $H$ :
\begin{tabular}{lllll}
$H=\#$ of heads & 0 & 1 & 2 & 3 \
\hline$P(H)$ & 0.125 & 0.375 & 0.375 & 0.125
\end{tabular}

What is the probability that Cora flips no more than 1 head?
$P($ no more than 1 head $)=$ $\square$

Question

Cora is playing a game that involves flipping three coins at once.
Let the random variable $H$ be the number of coins that land showing "heads". Here is the probability distribution for $H$ :
\begin{tabular}{lllll}
$H=\#$ of heads & 0 & 1 & 2 & 3 \
\hline$P(H)$ & 0.125 & 0.375 & 0.375 & 0.125
\end{tabular}

What is the probability that Cora flips no more than 1 head?
$P($ no more than 1 head $)=$ $\square$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ To find the probability of Cora flipping no more than 1 head, we need to sum the probabilities of getting 0 heads and 1 head. ‖ ‖ step 2 ⋮ The probability of getting 0 heads is given as $P(H=0) = 0.125$. ‖ ‖ step 3 ⋮ The probability of getting 1 head is given as $P(H=1) = 0.375$. ‖ ‖ step 4 ⋮ Summing these probabilities gives us $P(H=0) + P(H=1) = 0.125 + 0.375$. ‖ ‖ step 5 ⋮ Using the asksia-ll calculation list, we know that $0.125 + 0.375 = 0.5$. ‖ ‖ step 6 ⋮ Therefore, the probability that Cora flips no more than 1 head is $0.5$. ‖ ∻Answer∻ ⚹ $P($ no more than 1 head $) = 0.5$ ⚹ ∻Key Concept∻ ⚹Sum of Probabilities⚹ ∻Explanation∻ ⚹To find the total probability of multiple mutually exclusive events, we sum the individual probabilities of these events. In this case, the events are flipping 0 or 1 head.⚹◊What is the formula to calculate the probability of flipping no more than 1 head in this scenario?⍭ Generate me a similar question◊

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