Question

Math

Posted 5 months ago

```
Cora is playing a game that involves flipping three coins at once.
Let the random variable $H$ be the number of coins that land showing "heads". Here is the probability distribution for $H$ :
\begin{tabular}{lllll}
$H=\#$ of heads & 0 & 1 & 2 & 3 \\
\hline$P(H)$ & 0.125 & 0.375 & 0.375 & 0.125
\end{tabular}
What is the probability that Cora flips no more than 1 head?
$P($ no more than 1 head $)=$ $\square$
```

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Answer from Sia

Posted 5 months ago

Solution by Steps

step 1

To find the probability of Cora flipping no more than 1 head, we need to sum the probabilities of getting 0 heads and 1 head

step 2

The probability of getting 0 heads is given as $P(H=0) = 0.125$

step 3

The probability of getting 1 head is given as $P(H=1) = 0.375$

step 4

Summing these probabilities gives us $P(H=0) + P(H=1) = 0.125 + 0.375$

step 5

Using the asksia-ll calculation list, we know that $0.125 + 0.375 = 0.5$

step 6

Therefore, the probability that Cora flips no more than 1 head is $0.5$

Answer

$P($ no more than 1 head $) = 0.5$

Key Concept

Sum of Probabilities

Explanation

To find the total probability of multiple mutually exclusive events, we sum the individual probabilities of these events. In this case, the events are flipping 0 or 1 head.

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