Cora is playing a game that involves flipping three coins at once.
Let the random variable $H$ be the number of coins that land showing "heads". Here is the probability distribution for $H$ :
\begin{tabular}{lllll}
$H=$ \# of heads & 0 & 1 & 2 & 3 \
\hline$P(H)$ & 0.125 & 0.375 & 0.375 & 0.125
\end{tabular}

What is the probability that Cora flips no more than 1 head?
$P($ no more than 1 head $)=$ $\square$

Question

Cora is playing a game that involves flipping three coins at once.
Let the random variable $H$ be the number of coins that land showing "heads". Here is the probability distribution for $H$ :
\begin{tabular}{lllll}
$H=$ \# of heads & 0 & 1 & 2 & 3 \
\hline$P(H)$ & 0.125 & 0.375 & 0.375 & 0.125
\end{tabular}

What is the probability that Cora flips no more than 1 head?
$P($ no more than 1 head $)=$ $\square$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Calculate the probability of flipping no more than 1 head by adding the probabilities of flipping 0 heads and 1 head. ‖ ‖ step 2 ⋮ Use the given probabilities from the table: $P(H=0) = 0.125$ and $P(H=1) = 0.375$. ‖ ‖ step 3 ⋮ Add the probabilities: $P(H=0) + P(H=1) = 0.125 + 0.375$. ‖ ‖ step 4 ⋮ Perform the addition: $0.125 + 0.375 = 0.5$. ‖ ‖ step 5 ⋮ Convert the decimal to a fraction: $0.5 = \frac{1}{2}$. ‖ ∻Answer∻ ⚹ $P($ no more than 1 head $) = \frac{1}{2}$ ⚹ ∻Key Concept∻ ⚹Adding Probabilities of Mutually Exclusive Events⚹ ∻Explanation∻ ⚹To find the probability of a compound event where no more than one of several mutually exclusive outcomes occurs, we add the probabilities of each individual outcome. In this case, we add the probabilities of flipping 0 heads and 1 head to find the probability of flipping no more than 1 head.⚹◊What is the formula to calculate the probability of flipping no more than 1 head?⍭ Generate me a similar question◊

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