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Question
Math
Posted 7 months ago

Dr. Nunez wants to estimate the average lung capacity of adults in her state. She plans on taking a sample of nn adults to construct a 99%99 \% confidence interval for the mean lung capacity. She wants the margin of error to be no more than 100 mL100 \mathrm{~mL}. She's willing to use σ=300 mL\sigma=300 \mathrm{~mL} as an estimate for the population standard deviation.

Which of these is the smallest approximate sample size required to obtain the desired margin of error?

Choose 1 answer:
(A) 35 adults
(B) 45 adults
(C) 50 adults
(D) 55 adults
(E) 60 adults
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Answer from Sia
Posted 7 months ago
Solution by Steps
step 1
To find the smallest sample size required, we use the formula for the sample size for estimating a population mean with a given margin of error (M), population standard deviation (σ), and confidence level (c)
step 2
The formula for the sample size (n) is given by n=2(σerf1(c)M)2n = 2 \left(\frac{\sigma \cdot \text{erf}^{-1}(c)}{M}\right)^2. Here, erf1(c)\text{erf}^{-1}(c) is the inverse error function corresponding to the confidence level
step 3
Plugging in the values: M=100M = 100, σ=300\sigma = 300, and c=99%c = 99\%, we calculate the sample size
step 4
The calculation gives us a sample size of approximately 59.71, which we round up to the nearest whole number since we cannot have a fraction of a sample
Answer
The smallest approximate sample size required is 60 adults (Option E).
Key Concept
Sample Size Calculation for Population Mean Estimation
Explanation
The sample size is calculated using the margin of error, population standard deviation, and confidence level to ensure that the estimate of the population mean is within the desired precision. The sample size must be rounded up to the nearest whole number as we cannot have a fraction of a sample.

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