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青州's Question
Chemistry
Posted 4 months ago

Energy bar charts
For each of the situations described below, use an energy bar chart to represent the ways that energy is stored in the system and flows into or out of the system.
11. A cup of hot chocolate cools as it sits on the table. (10 points)
12 A tray of water (20C)\left(20^{\circ} \mathrm{C}\right) is placed in the freezer and turns into ice cubes (8C)\left(-8^{\circ} \mathrm{C}\right). (10 points)
Energy Fion
Fina

Quantitative problems
Be sure to show work and label quantities. Stiow the time-lemp kraph. Useful constants
334 J/g334 \mathrm{~J} / \mathrm{g} \quad Heat of fusion (Hi) (melting of freezing
2260 J/h2260 \mathrm{~J} / \mathrm{h} Heat of vaporization (Hy) (evaporating or condensing)
2.10 N/gC2.10 \mathrm{~N} / \mathrm{g}^{\circ} \mathrm{C} \quad Heat eapacity (c) of solid water
4. 18JgC18 \mathrm{Jg}^{\circ} \mathrm{C}
Heat capacity (c) of liquid water
13. How much enersy must be absorled by a 150 g150 \mathrm{~g} sample of wce at that melts?'10 points)
14. A 50.0 g samiple of hiquiat water freeres. How much oncory is involvod in this change? (10(10 points)
15. An ice cube tray full of rice (235g) at 79C-79^{\circ} \mathrm{C} is allowed to warm un to 0C0^{\prime} \mathrm{C}. but daes not melt. How much energy must be absorbed by the contents of the tray in order tor this to huppen? (10 points)
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Answer from Sia
Posted 4 months ago
Solution
1
Identify the process: The problem involves the phase change of water from liquid to solid (freezing) and the associated energy changes
2
Determine the mass of the sample: The mass of the liquid water sample is given as 50.0g50.0 \, \text{g}
3
Use the heat of fusion: The heat of fusion for water is 334J/g334 \, \text{J/g}. This is the amount of energy required to change 1 gram of water from liquid to solid at 0C0^\circ \text{C}
4
Calculate the energy involved: Multiply the mass of the water by the heat of fusion to find the total energy involved in the phase change. The formula is: Q=mΔHf Q = m \cdot \Delta H_f where Q Q is the energy, m m is the mass, and ΔHf \Delta H_f is the heat of fusion. Q=50.0g×334J/g=16700J Q = 50.0 \, \text{g} \times 334 \, \text{J/g} = 16700 \, \text{J}
Answer
16700J16700 \, \text{J}
Key Concept
Heat of fusion
Explanation
The heat of fusion is the amount of energy required to change a substance from the solid phase to the liquid phase at its melting point. In this problem, it is used to calculate the energy involved in freezing liquid water.

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