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ericzrf's Question
Math
Posted 6 months ago
Evaluate the indefinite integral. (Remember the constant of integration.)
e4x(5+e4x)8dx=
\int e^{4 x}\left(5+e^{4 x}\right)^{8} d x=

\square
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Answer from Sia
Posted 6 months ago
Solution by Steps
step 1
To integrate the function e4x(5+e4x)8 e^{4x}(5+e^{4x})^8 , we can use substitution. Let u=5+e4x u = 5+e^{4x} , then du=4e4xdx du = 4e^{4x}dx
step 2
To adjust for the 4 4 in du du , we multiply and divide the integral by 4 4 , giving us 14u8du \frac{1}{4} \int u^8 du
step 3
Now we integrate u8 u^8 with respect to u u to get 14u99+C \frac{1}{4} \cdot \frac{u^9}{9} + C , where C C is the constant of integration
step 4
Substituting back for u u , we get 136e4x(5+e4x)9+C \frac{1}{36} e^{4x}(5+e^{4x})^9 + C
Answer
136e4x(5+e4x)9+C \frac{1}{36} e^{4x}(5+e^{4x})^9 + C
Key Concept
Integration by Substitution
Explanation
To integrate a composite function like e4x(5+e4x)8 e^{4x}(5+e^{4x})^8 , we use substitution to simplify the integral into a form that is easier to integrate directly.

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