Given the following code snippet, what is true about the statement ptr
_
num
+
+
?
int num
[
5
]
=
{
1
,
2
,
3
,
4
,
5
}
;
int
*
*
ptr
_
num
=
num;
ptr
_
numt
+
;

Question

Given the following code snippet, what is true about the statement ptr
_
num
+
+
?
int num 
[
5
]
=
{
1
,
2
,
3
,
4
,
5
}
;
int 
*
*
 ﻿ptr
_
num 
=
 ﻿num;
ptr
_
numt
+
;

Accepted Answer

```c // Define an array of integers int num[5] = {1, 2, 3, 4, 5}; // Declare a pointer to a pointer to an integer int ****ptr_num; // Initialize ptr_num to point to the first element of the array num ptr_num = # // Increment ptr_num to point to the next integer in memory ptr_num++; ``` ∻Explanation∻ ⚹The statement `ptr_num++` increments the pointer `ptr_num` so that it points to the next integer in memory. However, since `ptr_num` is a pointer to a pointer, this code will not compile as intended. The correct declaration should be `int *ptr_num = num;` to point to the first element of the array.⚹ ∻Step-by-step Instruction∻ ‖ ▪ ⋮ Identify the error in the pointer declaration: `ptr_num` should be a pointer to an integer, not a pointer to a pointer. ‖ ‖ ▪ ⋮ Correct the declaration of `ptr_num` to `int *ptr_num = num;` to point to the first element of the array. ‖ ‖ ▪ ⋮ Explain that `ptr_num++` will then correctly increment the pointer to point to the next element in the array `num`. ‖ ∻Time Complexity∻ ⚹The time complexity is not applicable here as we are not discussing an algorithm with multiple steps or iterations.⚹ ∻Space Complexity∻ ⚹The space complexity is constant (O(1)) as the space used does not depend on the size of the input.⚹

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