Question

Math

Posted 6 months ago

```
Graph $y=2 \cos \left(\frac{1}{2} x\right)-1$ in the interactive widget.
Note that one moveable point always defines an extremum point in the graph and the other point always defines a neighbouring intersection with the midline.
```

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Answer from Sia

Posted 6 months ago

Solution by Steps

step 1

To find the integral of $6 \cos(1 + \sin(t))$ from $t=3$ to $t=0$, we use the fundamental theorem of calculus

step 2

The Asksia-LL calculator has already computed this integral and provided the result

step 3

The result from the Asksia-LL calculator for the integral is approximately $1.6335888917$

step 4

To complete the calculation for the second part, we add 2 to the result from step 1

step 5

Adding 2 to the integral result gives us $1.6335888917 + 2 \approx 3.6335888917$

[question 1] Answer

The result of the calculation $2 + \text{(result from step 1)}$ is approximately $3.6335888917$.

Key Concept

Integration and the fundamental theorem of calculus

Explanation

The integral of a function over an interval can be found using the fundamental theorem of calculus, and additional arithmetic operations can be applied to this result as needed.

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