How many atoms of hydrogen are present in 14.78 grams of nicotine, $\mathrm{C} 8 \mathrm{~N} 2 \mathrm{H} 14$

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∻Solution∻ ‖ 1 ⋮ **Calculate the molar mass of nicotine**: To find the number of hydrogen atoms in a given mass of nicotine, we first need to calculate the molar mass of nicotine, which has the molecular formula $\mathrm{C}_8\mathrm{N}_2\mathrm{H}_{14}$. The molar mass is the sum of the atomic masses of all the atoms in the molecule. ‖ ‖ 2 ⋮ **Determine the number of moles of nicotine**: Using the molar mass from step 1, we can calculate the number of moles of nicotine in 14.78 grams by using the formula: number of moles $= \frac{ ext{mass in grams}}{ ext{molar mass}}$. ‖ ‖ 3 ⋮ **Calculate the number of hydrogen atoms**: Since each molecule of nicotine contains 14 hydrogen atoms, we can find the total number of hydrogen atoms by multiplying the number of moles of nicotine by Avogadro's number ($6.022 imes 10^{23}$ atoms/mole) and then by 14. ‖ ∻Answer∻ ⚹ [Insert final answer here] ⚹ ∻Key Concept∻ ⚹ Determining the number of atoms in a given mass of a compound requires knowledge of the compound's molar mass, the number of moles, and Avogadro's number. ⚹ ∻Explanation∻ ⚹ To find the number of hydrogen atoms in a sample of nicotine, we calculate the molar mass of nicotine, determine the number of moles of nicotine in the given mass, and then use Avogadro's number to find the total number of hydrogen atoms. ⚹◊How can you calculate the number of moles of hydrogen in 14.78 grams of nicotine?⍭ Generate me a similar question◊

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