If $\mathrm{CH}_{3} \mathrm{Cl}$ and $\mathrm{CCl}_{3} \mathrm{H}$ are mixed $\mathrm{CH}_{4}$ and $\mathrm{CCl}_{4}$ will result. Why?

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∻Solution∻ ‖ 1 ⋮ **Identify the reactants and products**: The given reaction involves the mixing of $CH_3Cl$ (methyl chloride) and $CCl_3H$ (chloroform) to produce $CH_4$ (methane) and $CCl_4$ (carbon tetrachloride). ‖ ‖ 2 ⋮ **Analyze the reaction mechanism**: This reaction is a type of halogen exchange reaction where the chlorine atoms are exchanged between the reactants. The reaction can be represented as: $$ CH_3Cl + CCl_3H \rightarrow CH_4 + CCl_4 $$ Here, the chlorine atom from $CH_3Cl$ is transferred to $CCl_3H$, resulting in the formation of $CH_4$ and $CCl_4$. ‖ ‖ 3 ⋮ **Consider the stability of products**: Methane ($CH_4$) and carbon tetrachloride ($CCl_4$) are both stable compounds. Methane is a simple hydrocarbon, and carbon tetrachloride is a stable chlorinated compound. The reaction proceeds because the products are more stable than the reactants. ‖ ∻Answer∻ ⚹ The reaction between $CH_3Cl$ and $CCl_3H$ results in the formation of $CH_4$ and $CCl_4$ due to the exchange of chlorine atoms, leading to the formation of stable products. ⚹ ∻Key Concept∻ ⚹ Halogen exchange reaction ⚹ ∻Explanation∻ ⚹ The reaction involves the exchange of chlorine atoms between $CH_3Cl$ and $CCl_3H$, resulting in the formation of stable products $CH_4$ and $CCl_4$. ⚹◊What type of reaction is occurring when $CH_{3}Cl$ and $CCl_{3}H$ are mixed to form $CH_{4}$ and $CCl_{4}$?⍭ Generate me a similar question◊

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