If two carriers (heterozygotes) have children, the probability that their first two children are affected by the trait is

Group of answer choices
$1 / 16$
$1 / 4$
$3 / 4$
$15 / 16$

Question

If two carriers (heterozygotes) have children, the probability that their first two children are affected by the trait is

Group of answer choices
$1 / 16$
$1 / 4$
$3 / 4$
$15 / 16$

Accepted Answer

***A*** ∻Key Concept∻ ⚹Probability of inheriting a recessive trait⚹ ∻Explanation∻ ⚹When two heterozygous carriers (Aa) have children, the probability of each child being affected by a recessive trait (aa) is $1/4$. The probability that both of their first two children are affected is $(1/4) imes (1/4) = 1/16$.⚹◊What is the probability of both children being affected by the trait if two carriers (heterozygotes) have children?⍭ Generate me a similar question◊

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