In Java; Set hasDigit to true if the 3-character passCode contains a digit. If you could tell me why the code I wrote isn't working I'd be thankful.import java.util.Scanner;public class CheckingPasscodes {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);boolean hasDigit;String passCode;hasDigit = false;passCode = scnr.next();let0 = userInput.charAt(0);let1 = userInput.charAt(1);let2 = userInput.charAt(2); if ((Character.isDigit(let0) || Character.isDigit(let1) || Character.isDigit(let2)){hasDigit = true;}if (hasDigit) {System.out.println("Has a digit.");}else {System.out.println("Has no digit.");}

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```java import java.util.Scanner; public class CheckingPasscodes { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); boolean hasDigit; // Declare a boolean variable to store if a digit is present String passCode; // Declare a String variable to store the passcode hasDigit = false; // Initialize hasDigit to false passCode = scnr.next(); // Read the passcode from user input // Correct variable names from userInput to passCode char let0 = passCode.charAt(0); // Get the first character of the passcode char let1 = passCode.charAt(1); // Get the second character of the passcode char let2 = passCode.charAt(2); // Get the third character of the passcode // Correct the if condition by adding a closing parenthesis if ((Character.isDigit(let0) || Character.isDigit(let1) || Character.isDigit(let2))) { hasDigit = true; // Set hasDigit to true if any character is a digit } // Output the result based on the value of hasDigit if (hasDigit) { System.out.println("Has a digit."); } else { System.out.println("Has no digit."); } } } ``` ∻Explanation∻ ⚹The code provided by the student had two issues: incorrect variable names (userInput should be passCode) and a missing closing parenthesis in the if condition. The corrected code checks each character of the passCode to determine if it contains a digit and sets the hasDigit flag accordingly.⚹ ∻Step-by-step Instruction∻ ‖ ▪ ⋮ Identify the issues in the provided code: incorrect variable names and missing parenthesis. ‖ ‖ ▪ ⋮ Correct the variable names to match the declared variable passCode. ‖ ‖ ▪ ⋮ Add the missing closing parenthesis in the if condition to fix the syntax error. ‖ ‖ ▪ ⋮ Test the corrected code with different passCode inputs to ensure it works as expected. ‖ ∻Time Complexity∻ ⚹The time complexity is O(1) because the code checks a fixed number of characters (3) and does not depend on the size of the input.⚹ ∻Space Complexity∻ ⚹The space complexity is O(1) as the amount of memory used does not scale with the size of the input; it uses a fixed amount of space for the variables.⚹

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