In double precision operations, the instructions are different. For example, sub.s in single precision should be sub.d in double precision. The registers are used in pairs since double precision will double the size of the value storage. The static variable should be defined as
.
double as well. Therefore, the registers are occupied in pairs to store the double
-
size value and only the even
-
numbered register can be used for programming while the odd
-
numbered register will be the extension of the evennumbered register. For example, only $
�
0
,
$
�
2
,
$
�
4
,
$
�
6
,
$
�
8
,
etc. can be used for double precision operations.
Write a program named lab
1
0
-
double.s
.
It can receive the input of the user in Celsius and do the reverse conversion of the given snippet. Requirements:
(
1
)
Using double precision operations.
(
2
)
Prompt the user to type in Celsius and the program can display Fahrenheit.
(
3
)
Paste the screenshot of the result as well as your source code.

Question

In double precision operations, the instructions are different. For example, sub.s in single precision should be sub.d in double precision. The registers are used in pairs since double precision will double the size of the value storage. The static variable should be defined as 
.
double as well. Therefore, the registers are occupied in pairs to store the double
-
size value and only the even
-
numbered register can be used for programming while the odd
-
numbered register will be the extension of the evennumbered register. For example, only $
�
0
,
$
�
2
,
$
�
4
,
$
�
6
,
$
�
8
,
 ﻿etc. can be used for double precision operations.
Write a program named lab
1
0
-
double.s
.
 ﻿It can receive the input of the user in Celsius and do the reverse conversion of the given snippet. Requirements: 
(
1
)
 ﻿Using double precision operations. 
(
2
)
 ﻿Prompt the user to type in Celsius and the program can display Fahrenheit. 
(
3
)
 ﻿Paste the screenshot of the result as well as your source code.

Accepted Answer

```assembly # Data segment to store user prompt and conversion constants .data prompt: .asciiz "Enter temperature in Celsius: " celsiusToFahrenheitFactor: .double 1.8 celsiusToFahrenheitOffset: .double 32.0 # Text segment for the program's instructions .text .globl main # main function to execute the program main: # Print prompt to the user li $v0, 4 la $a0, prompt syscall # Read double-precision floating-point number from user li $v0, 6 syscall # Move the user input to a double-precision register mov.d $f12, $f0 # Multiply the Celsius temperature by 1.8 (double precision) ldc1 $f2, celsiusToFahrenheitFactor mul.d $f4, $f12, $f2 # Add 32 to the result (double precision) ldc1 $f6, celsiusToFahrenheitOffset add.d $f8, $f4, $f6 # Move the result to $f0 for printing mov.d $f0, $f8 # Print the result as double-precision floating-point number li $v0, 3 syscall # Exit the program li $v0, 10 syscall ``` ```assembly # main function that tests the conversion from Celsius to Fahrenheit # Note: This is a hypothetical test scenario as MIPS assembly does not support assertions natively # The test cases are described as comments # Test case 1: Convert 0 Celsius to Fahrenheit # Expected output: 32.0 Fahrenheit # Test case 2: Convert 100 Celsius to Fahrenheit # Expected output: 212.0 Fahrenheit ``` ∻Explanation∻ ⚹The provided MIPS assembly code reads a double-precision floating-point number from the user, converts it from Celsius to Fahrenheit using double-precision arithmetic, and prints the result.⚹ ∻Step-by-step Instruction∻ ‖ ▪ ⋮ Define the data segment with user prompt and conversion constants for Celsius to Fahrenheit. ‖ ‖ ▪ ⋮ Define the text segment and declare the main function as global. ‖ ‖ ▪ ⋮ Print the prompt to the user to enter the temperature in Celsius. ‖ ‖ ▪ ⋮ Read the user input as a double-precision floating-point number. ‖ ‖ ▪ ⋮ Perform the conversion calculation using double-precision multiplication and addition. ‖ ‖ ▪ ⋮ Print the result as a double-precision floating-point number. ‖ ‖ ▪ ⋮ Exit the program. ‖ ∻Time Complexity∻ ⚹The time complexity is constant, O(1), because the sequence of instructions is executed once and does not depend on the size of the input.⚹ ∻Space Complexity∻ ⚹The space complexity is also constant, O(1), as the program uses a fixed amount of memory for storing the prompt, constants, and registers for calculations.⚹

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