Layla has a coin that has a $60 \%$ chance of showing heads each time it is flipped. She is going to flip the coin 5 times. Let $X$ represent the number of heads she gets.

What is the probability that she gets more than 3 heads?
You may round your answer to the nearest hundredth.
$$
P(X3)=
$$

Question

Layla has a coin that has a $60 \%$ chance of showing heads each time it is flipped. She is going to flip the coin 5 times. Let $X$ represent the number of heads she gets.

What is the probability that she gets more than 3 heads?
You may round your answer to the nearest hundredth.
$$
P(X>3)=
$$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Identify the type of probability distribution and the relevant parameters. ‖ ‖ step 2 ⋮ Calculate the probability of getting exactly 4 heads: $P(X=4)$. ‖ ‖ step 3 ⋮ Calculate the probability of getting exactly 5 heads: $P(X=5)$. ‖ ‖ step 4 ⋮ Add the probabilities from steps 2 and 3 to find $P(X>3)$. ‖ ∻[question number] Answer∻ ⚹ $P(X>3) \approx 0.34$ ⚹ ∻Key Concept∻ ⚹Binomial Probability Distribution⚹ ∻Explanation∻ ⚹The probability of getting more than 3 heads in 5 flips of a coin with a 60% chance of heads is calculated using the binomial probability formula for the exact outcomes of 4 and 5 heads, then summing these probabilities.⚹◊What is the formula to calculate the probability of getting more than 3 heads in 5 coin flips with a 60% chance of landing heads⍭ Generate me a similar question◊

Sia