Asksia AI LOGO

Sia

Question
Math
Posted 7 months ago

Let SS be a surface in 3D described by the equation 3x+sin(y)+z2=03 x+\sin (y)+z^{2}=0.

What is the equation of the plane tangent to SS at (3,π,3)(-3, \pi, 3) ?
Choose 1 answer:
(A) 3(x3)(y+π)+6(z+3)=03(x-3)-(y+\pi)+6(z+3)=0
(B) 3(x+3)(yπ)+6(z3)=03(x+3)-(y-\pi)+6(z-3)=0
(C) 2(z6)=02(z-6)=0
() 3(x+3)π(y1)+3(z6)=0-3(x+3)-\pi(y-1)+3(z-6)=0
Sign in to unlock the answer
Answer from Sia
Posted 7 months ago
Solution by Steps
step 2
The gradient of the surface SS described by f(x,y,z)=3x+sin(y)+z2f(x, y, z) = 3x + \sin(y) + z^2 is f=(fx,fy,fz)\nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right)
step 3
From the asksia-ll calculation, we have the partial derivatives at the point (3,π,3)(-3, \pi, 3): fx=3\frac{\partial f}{\partial x} = 3, fy=cos(y)\frac{\partial f}{\partial y} = \cos(y), and fz=2z\frac{\partial f}{\partial z} = 2z
step 4
Evaluating the partial derivatives at (3,π,3)(-3, \pi, 3), we get f(3,π,3)=(3,0,6)\nabla f(-3, \pi, 3) = (3, 0, 6)
step 5
The equation of the tangent plane is given by f(xx0,yy0,zz0)=0\nabla f \cdot (x - x_0, y - y_0, z - z_0) = 0, where (x0,y0,z0)(x_0, y_0, z_0) is the point of tangency
step 6
Substituting the gradient and the point (3,π,3)(-3, \pi, 3) into the equation of the tangent plane, we get 3(x+3)+0(yπ)+6(z3)=03(x + 3) + 0(y - \pi) + 6(z - 3) = 0
step 7
Simplifying the equation, we obtain 3(x+3)+6(z3)=03(x + 3) + 6(z - 3) = 0
step 8
The final equation of the tangent plane is 3x+9+6z18=03x + 9 + 6z - 18 = 0, which simplifies to 3x+6z9=03x + 6z - 9 = 0
[question 1] Answer
B
Key Concept
Gradient and Tangent Plane
Explanation
The equation of a tangent plane to a surface at a given point can be found using the gradient of the surface function at that point and the point of tangency.

Not the question you are looking for? Ask here!

Enter question by text

Enter question by image

Unlock Smarter Learning with AskSia Super!

Join Super, our all-in-one AI solution that can greatly improve your learning efficiency.

30% higher accuracy than GPT-4o
Entire learning journey support
The most student-friendly features
Study Other Question