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Question
Math
Posted 9 months ago
Math Problem: Solve for x:32x+19=10xx: 3^{2 x}+19=10^{x}.
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Answer from Sia
Posted 9 months ago
Solution by Steps
step 1
To solve the equation 32x+19=10x3^{2x} + 19 = 10^x, we first need to isolate the terms with the variable xx
step 2
However, there is no straightforward algebraic method to isolate xx since it is in the exponent of different bases. We need to use numerical methods or graphing techniques to find the solution for xx
step 3
According to the asksia-ll calculation list, the solution provided is x=2x = 2. This means that when xx is substituted back into the original equation, both sides should be equal
step 4
Let's verify the solution by substituting x=2x = 2 into the original equation: 322+193^{2 \cdot 2} + 19 should equal 10210^2
step 5
Calculating the left side: 322+19=34+19=81+19=1003^{2 \cdot 2} + 19 = 3^4 + 19 = 81 + 19 = 100
step 6
Calculating the right side: 102=10010^2 = 100
step 7
Since both sides are equal when x=2x = 2, the solution x=2x = 2 is verified
Answer
x=2x = 2
Key Concept
Solving Exponential Equations
Explanation
To solve an exponential equation where the variable is in the exponent, we often need to use numerical methods or graphing if the equation cannot be simplified to have the same base. In this case, the solution was found to be x=2x = 2, which satisfies the original equation.

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