Question

Math

Posted 4 months ago

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Olivia works at a company that creates mobile phones. She wanted to estimate the mean amount of time their new phone's battery lasts with regular use after a full charge. She took a random sample of 6 of these phones and randomly assigned each of them to a volunteer. She instructed them to fully charge the phones and use them as they regularly would until the battery died (without recharging the phone). Here are the data they reported:
\begin{tabular}{rrrrrrr}
Phone & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline Battery life (hours) & 8.0 & 6.0 & 10.5 & 9.0 & 8.5 & 12 \\
Mean & $\bar{x}=9$ hours & & & & &
\end{tabular}
Standard deviation $\quad s_{x}=2.07$ hours
Assume that all conditions for inference are met.
Which of the following is a $90 \%$ confidence interval for the mean battery life (in hours)?
Choose 1 answer:
(A) $9 \pm 1.4$
(B) $9 \pm 1.7$
(C) $9 \pm 2.0$
(D) $9 \pm 2.07$
```

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Answer from Sia

Posted 4 months ago

Solution by Steps

step 2

Given that the sample mean $x̄ = 9$ hours, the sample standard deviation $s = 2.07$ hours, the sample size $n = 6$, and the confidence level $c = 90\%$, we can plug these values into the formula

step 3

The critical value $t_{(1 - c)/2}$ for a 90% confidence interval with 5 degrees of freedom (since $n - 1 = 6 - 1 = 5$) can be found in a t-distribution table or using a calculator

step 4

The calculation yields a confidence interval of $9 ± 2.07$. This matches option (D) from the multiple-choice answers provided

D

Key Concept

T-interval for a population mean

Explanation

The T-interval formula is used to estimate the population mean from a sample mean, standard deviation, and size, with a given confidence level.

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