Point $A$ is at $(-2,4)$ and point $B$ is at $(7,3)$.
What is the midpoint of line segment $\overline{A B}$ ?

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∻Solution by Steps∻ ‖ step 1 ⋮ To find the midpoint of a line segment with endpoints $(-2, 4)$ and $(7, 3)$, we average the x-coordinates and the y-coordinates separately. ‖ ‖ step 2 ⋮ The midpoint $M$ has coordinates $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$. ‖ ‖ step 3 ⋮ Substituting the given coordinates into the midpoint formula: $M = \left(\frac{-2 + 7}{2}, \frac{4 + 3}{2}\right)$. ‖ ‖ step 4 ⋮ Calculating the averages: $M = \left(\frac{5}{2}, \frac{7}{2}\right)$. ‖ ‖ step 5 ⋮ Converting the fractions to decimal form: $M = (2.5, 3.5)$. ‖ ∻[1] Answer∻ ⚹ The midpoint of line segment $\overline{AB}$ is $(2.5, 3.5)$. ⚹ ∻Key Concept∻ ⚹Midpoint of a Line Segment⚹ ∻Explanation∻ ⚹The midpoint of a line segment with endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is found by averaging the x-coordinates and the y-coordinates separately to get the midpoint coordinates $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$.⚹◊What is the formula to find the midpoint of a line segment given the coordinates of the endpoints?⍭ Generate me a similar question◊

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