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Math
Posted over 2 years ago

Q4.7 End Behavior of Polynomials II
1 Point
Determine the end behavior of the graph of f(x)=−5x4−x3+3x2+7f(x)=-5 x^{4}-x^{3}+3 x^{2}+7 : as x→∞,f(x)→…x \rightarrow \infty, f(x) \rightarrow \ldots; (0.5pt)(0.5 \mathrm{pt})
∞\infty
−∞-\infty
as x→−∞,f(x)→x \rightarrow-\infty, f(x) \rightarrow \qquad . (0.5pt)(0.5 \mathrm{pt})
∞\infty
−∞-\infty
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Answer from Sia
Posted over 2 years ago
Solution by Steps
step 1
Identify the leading term of the polynomial f(x)=−5x4−x3+3x2+7f(x) = -5x^4 - x^3 + 3x^2 + 7. The leading term is −5x4-5x^4
step 2
Determine the end behavior as x→∞x \rightarrow \infty. Since the leading term −5x4-5x^4 has a negative coefficient and an even exponent, as x→∞x \rightarrow \infty, f(x)→−∞f(x) \rightarrow -\infty
step 3
Determine the end behavior as x→−∞x \rightarrow -\infty. Similarly, since the leading term −5x4-5x^4 has a negative coefficient and an even exponent, as x→−∞x \rightarrow -\infty, f(x)→−∞f(x) \rightarrow -\infty
Answer
As x→∞,f(x)→−∞x \rightarrow \infty, f(x) \rightarrow -\infty
As x→−∞,f(x)→−∞x \rightarrow -\infty, f(x) \rightarrow -\infty
Key Concept
End Behavior of Polynomials
Explanation
The end behavior of a polynomial function is determined by its leading term. For a polynomial with a negative leading coefficient and an even exponent, the function will approach −∞-\infty as xx approaches both ∞\infty and −∞-\infty.

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