Solve for $x$. Enter the solutions from least to greatest.
$$
x^{2}-2 x-35=0
$$
lesser $x=$ $\square$
greater $x=$ $\square$

Question

Solve for $x$. Enter the solutions from least to greatest.
$$
x^{2}-2 x-35=0
$$
lesser $x=$ $\square$
greater $x=$ $\square$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ To solve the quadratic equation $x^2 - 2x - 35 = 0$, we look for factors of -35 that add up to -2. ‖ ‖ step 2 ⋮ The factors of -35 that add up to -2 are -7 and 5. ‖ ‖ step 3 ⋮ We rewrite the quadratic equation as $(x - 7)(x + 5) = 0$. ‖ ‖ step 4 ⋮ Set each factor equal to zero: $x - 7 = 0$ or $x + 5 = 0$. ‖ ‖ step 5 ⋮ Solve for $x$ in each equation: $x = 7$ or $x = -5$. ‖ ∻Answer∻ ⚹ lesser $x=$ $-5$ ⚹ ⚹ greater $x=$ $7$ ⚹ ∻Key Concept∻ ⚹Factoring a quadratic equation⚹ ∻Explanation∻ ⚹To solve a quadratic equation by factoring, we find two numbers that multiply to the constant term (-35) and add to the linear coefficient (-2). We then set each factor equal to zero and solve for $x$.⚹◊What are the solutions for $x$ in the quadratic equation $x^{2} - 2x - 35 = 0$ when arranged from least to greatest?⍭ Generate me a similar question◊

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