Solve the system of equations.
$$
\begin{array}{l}
13 x-6 y=22 \
x=y+6 \
x=\square \
y=\square
\end{array}
$$

Question

Solve the system of equations.
$$
\begin{array}{l}
13 x-6 y=22 \
x=y+6 \
x=\square \
y=\square
\end{array}
$$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Substitute the second equation $x = y + 6$ into the first equation $13x - 6y = 22$. ‖ ‖ step 2 ⋮ Replace $x$ with $y + 6$ in the first equation to get $13(y + 6) - 6y = 22$. ‖ ‖ step 3 ⋮ Simplify the equation: $13y + 78 - 6y = 22$. ‖ ‖ step 4 ⋮ Combine like terms to get $7y + 78 = 22$. ‖ ‖ step 5 ⋮ Subtract 78 from both sides to get $7y = -56$. ‖ ‖ step 6 ⋮ Divide both sides by 7 to solve for $y$: $y = -8$. ‖ ‖ step 7 ⋮ Substitute $y = -8$ back into the second equation $x = y + 6$ to find $x$. ‖ ‖ step 8 ⋮ Solve for $x$: $x = -8 + 6$. ‖ ‖ step 9 ⋮ Simplify to find $x = -2$. ‖ ∻Answer∻ ⚹ $x = -2$ and $y = -8$ ⚹ ∻Key Concept∻ ⚹Substitution Method⚹ ∻Explanation∻ ⚹To solve a system of equations where one equation is already solved for one variable, substitute that expression into the other equation and solve for the remaining variable.⚹◊What is the value of y in the system of equations after finding x = -2?⍭ Generate me a similar question◊

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