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Math
Posted 10 months ago
Statement 1 | Suppose {s_n} and {t_n} are sequences of complex numbers such that lim_n→∞ s_n = s and lim_n→∞ tn = t. lim_n→∞ s_nt_n = st. Statement 2 | There exists a bounded sequence of real numbers with no convergent subsequence.
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Answer from Sia
Posted 10 months ago
Solution by Steps
step 1
To find the definite integral of x4 x^4 from x=3 x = 3 to x=5 x = 5 , we use the power rule for integration
step 2
The power rule for integration states that the integral of xn x^n is xn+1n+1 \frac{x^{n+1}}{n+1} plus a constant of integration
step 3
Applying the power rule to x4 x^4 , we get x55 \frac{x^5}{5}
step 4
We evaluate this antiderivative from x=3 x = 3 to x=5 x = 5
step 5
The definite integral is [x55]35=555355 \left[\frac{x^5}{5}\right]_3^5 = \frac{5^5}{5} - \frac{3^5}{5}
step 6
Calculating the values, we get 312552435=28825 \frac{3125}{5} - \frac{243}{5} = \frac{2882}{5}
step 7
The result is 28825 \frac{2882}{5} or 576.4 576.4 in decimal form
Answer
28825 \frac{2882}{5} or 576.4 576.4
Key Concept
Definite Integral and Power Rule for Integration
Explanation
The definite integral of a power function xn x^n from a a to b b is found using the power rule, which involves finding the antiderivative and evaluating it at the upper and lower limits of integration. The result is the net area under the curve from a a to b b .


Regarding the student's question about sequences:

Solution by Steps
step 1
Statement 1 is a property of limits of sequences of complex numbers
step 2
If limnsn=s \lim_{n \to \infty} s_n = s and limntn=t \lim_{n \to \infty} t_n = t , then limn(sntn)=st \lim_{n \to \infty} (s_n t_n) = st
step 3
This follows from the limit laws for sequences, which state that the limit of a product is the product of the limits, provided that both limits exist
Answer
True
step 1
Statement 2 is about bounded sequences of real numbers
step 2
A bounded sequence is one where all terms of the sequence are within some fixed distance from a particular point
step 3
The Bolzano-Weierstrass theorem states that every bounded sequence in Rn\mathbb{R}^n has a convergent subsequence
step 4
Therefore, it is not possible for a bounded sequence of real numbers to have no convergent subsequence
Answer
False
Key Concept
Limits of Sequences and Bolzano-Weierstrass Theorem
Explanation
Statement 1 is true due to the limit laws for sequences. Statement 2 is false because the Bolzano-Weierstrass theorem guarantees that every bounded sequence of real numbers has at least one convergent subsequence.

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