Question

Chemistry

Posted 5 months ago

`The diffusion coefficient of $\mathrm{Ti}$ is $2.0 \times 10^{-5} \mathrm{~cm}^{2} \mathrm{~s}^{-1}$ and that for $\mathrm{Cd}^{2+}$ is $0.72 \times 10^{-5} \mathrm{~cm}^{2} \mathrm{~s}^{-1}$. If a I $\mathrm{mM}$ solution of $\mathrm{Cd}^{2+}$ gives a diffusion current of $8.15 \mu \mathrm{A}$, what will be the diffusion current for a $1 \mathrm{mM}$ solution of $T i^{+}$using the same polarographic cell?`

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Answer from Sia

Posted 5 months ago

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Answer

$I_{d,\mathrm{Ti}} \approx 13.9 \mu \mathrm{A}$

Key Concept

Diffusion current in polarography is proportional to the diffusion coefficient to the power of $2/3$ when all other variables are constant.

Explanation

The diffusion current for $\mathrm{Ti}^{+}$ is calculated using the Ilkovic equation and the known diffusion current for $\mathrm{Cd}^{2+}$, taking into account the different diffusion coefficients of $\mathrm{Ti}$ and $\mathrm{Cd}^{2+}$.

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