Asksia AI LOGO

Sia

Question
Math
Posted 5 months ago

The distribution of resting pulse rates of all students at Santa Maria high school was approximately normal with mean μ=80\mu=80 beats per minute and standard deviation σ=9\sigma=9 beats per minute.

The school nurse plans to provide additional screening to students whose resting pulse rates are in the top 30%30 \% of the students who were tested.

What is the minimum resting pulse rate at that school for students who will receive additional screening?

Choose 1 answer:
A) 76 beats per minute
(B) 85 beats per minute
(C) 87 beats per minute
D) 89 beats per minute
(E) 94 beats per minute
Sign in to unlock the answer
Answer from Sia
Posted 5 months ago
Solution by Steps
step 2
Using the standard normal distribution table or a calculator, we find that the z-score for the 70th percentile is approximately 0.52
step 3
We can now use the z-score formula to find the corresponding pulse rate: z=Xμσz = \frac{X - \mu}{\sigma}, where XX is the pulse rate, μ\mu is the mean, and σ\sigma is the standard deviation
step 4
Solving for XX gives us X=zσ+μX = z \cdot \sigma + \mu. Substituting the values, we get X=0.529+80X = 0.52 \cdot 9 + 80
step 5
Calculating the value of XX, we find that the minimum pulse rate is X=4.68+80=84.68X = 4.68 + 80 = 84.68 beats per minute
B
Key Concept
Percentiles and z-scores in a normal distribution
Explanation
To find a specific percentile in a normal distribution, we use the z-score that corresponds to that percentile and then translate it back to the original scale using the mean and standard deviation.

Not the question you are looking for? Ask here!

Enter question by text

Enter question by image

Upgrade to Asksia Pro

Join a AskSia's Pro Plan, and get 24/7 AI tutoring for your reviews, assignments, quizzes and exam preps.

Unlimited chat query usages
Strong algorithms that better know you
Early access to new release features
Study Other Question