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Sia

子心's Question
Computer Science
Posted 5 months ago
game_groups[-1].add(game) IndexError: list index out of range
The games now need to be scheduled, which will happen in two steps. Your first task is to group
together games that can be played simultaneously into game groups. The requirements for the game
groups are:
• People are not double-booked: each person is involved in at most one game in any game group.,
either as a player or referee
• Games are played once: each game is in exactly one game group
Each game group will be played in a single time slot, so the committee wants the smallest number of
game groups possible.
Implement your solution as a Python function of the form
def gameGroups ( assignedReferees ):
where assignedReferees is in the same format as you returned in the previous question, i.e. as a
dictionary with games as keys and referees as values. Your output should be a schedule in a data
structure of the form
Page 2
# list of timeslots
# each timeslot is a set of games
# each game is a pair ( player1 , player2 )
[
{ ( " Ashley " , " Bob " ) , ( " Charlie " , " Dave " ) } ,
{ ( " Bob " , " Charlie " ) , ( " Rene " , " Elaine " ) }
]
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Answer from Sia
Posted 5 months ago
python
python
Explanation
The function "gameGroups" groups games into time slots such that no person is double-booked.
Step-by-step Instruction
Create a list to hold the game groups (time slots)
Create a set to keep track of people who are already scheduled in the current time slot
Iterate over the games and their assigned referees
Check if any of the players or the referee are already scheduled in the current time slot
If they are, create a new time slot (game group)
Add the game to the current time slot
Add the players and the referee to the scheduled people set
Return the list of game groups
Time Complexity
The time complexity is O(n)O(n) where nn is the number of games.
Space Complexity
The space complexity is O(n)O(n) for storing the game groups and scheduled people.

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