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The mass of a single iron atom is $9.28 \times 100^{-23}$ grams. How many iron atoms would there be in 74.8 milligrams of iron?
atoms
The mass of a single iron atom is $\mathbf{9 . 2 8 \times 1 0 ^ { - 2 3 }}$ grams. How many iron atoms would there be in $\mathbf{7 4 . 8}$ milligrams of iron?
$\square$ atoms
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Answer from Sia

Posted 4 months ago

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To calculate the number of iron atoms in 74.8 milligrams of iron, we need to use the given mass of a single iron atom and convert the total mass from milligrams to grams.
First, we convert 74.8 milligrams to grams:
$74.8 \text{ mg} \times \frac{1 \text{ g}}{1000 \text{ mg}} = 0.0748 \text{ g}$
Next, we use the mass of a single iron atom to find the number of atoms:
$\frac{0.0748 \text{ g}}{9.28 \times 10^{-23} \text{ g/atom}}$
Now, we calculate the number of atoms:
$\frac{0.0748}{9.28 \times 10^{-23}} \approx 8.06 \times 10^{20} \text{ atoms}$
Since we need to provide the answer in the format requested, we will not include the exact number but rather the process of how to get to the answer.
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Key Concept

Conversion and Avogadro's number

Explanation

To find the number of atoms in a given mass, convert the mass to grams and divide by the mass of a single atom.

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