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The radius of a aluminum atom is $\mathbf{1 4 3} \mathrm{pm}$. How many aluminum atoms would have to be laid side by side to span a distance of $4.10 \mathrm{~mm}$ ?
$\square$ atoms
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Answer from Sia

Posted 3 months ago

Solution

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Answer

The number of aluminum atoms that can be laid side by side to span a distance of 4.10 mm is approximately 14306 atoms.

Key Concept

Conversion of units and understanding atomic dimensions

Explanation

To determine how many atoms fit within a certain distance, we must ensure that both measurements are in the same unit. Then, we use the diameter of an atom to find out how many can be placed in a row to cover the given distance.

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