The radius of a aluminum atom is $\mathbf{1 4 3} \mathrm{pm}$. How many aluminum atoms would have to be laid side by side to span a distance of $4.10 \mathrm{~mm}$ ?
$\square$ atoms

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∻Solution∻ ‖ 1 ⋮ **Convert millimeters to picometers**: To compare the distance in millimeters with the size of an aluminum atom in picometers, we first need to convert the distance from millimeters to picometers. There are $1 imes 10^{12}$ picometers in a millimeter. ‖ ‖ 2 ⋮ **Calculate the number of aluminum atoms**: The diameter of an aluminum atom is twice its radius. To find out how many atoms fit side by side, divide the total distance in picometers by the diameter of one aluminum atom in picometers. ‖ ∻Answer∻ ⚹ The number of aluminum atoms that can be laid side by side to span a distance of 4.10 mm is approximately 14306 atoms. ⚹ ∻Key Concept∻ ⚹ Conversion of units and understanding atomic dimensions ⚹ ∻Explanation∻ ⚹ To determine how many atoms fit within a certain distance, we must ensure that both measurements are in the same unit. Then, we use the diameter of an atom to find out how many can be placed in a row to cover the given distance. ⚹◊How can we calculate the number of aluminum atoms needed to span a distance of 4.10 mm based on the radius of an aluminum atom being 143 pm?⍭ Generate me a similar question◊

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